Forgettables
- ¹ÌºÐÇü½Ä (differential form): WorkÀÇ °è»ê°ú °°ÀÌ º¤ÅÍÀåÀ» ¼±ÀûºÐÇÒ ¶§ integrand¿¡ ÇØ´çÇÏ´Â °Í. ¿¹: \( \mathbf{F}({\mathbf x}) \cdot d\mathbf{s} = f_1(\mathbf{x})dx_1 + ... + f_n(\mathbf{x})dx_n \)
- ¿ÏÀü¹ÌºÐÇü½Ä (exact differential form): ÀáÀçÇÔ¼ö¸¦ °¡Áö´Â ¹ÌºÐÇü½Ä
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- Àü¹ÌºÐ (total differentiation): Á¤Àü±âÀå¿¡¼ ¼±ÀûºÐÇÒ ¶§ ÀüÀ§ÀÎ ½ºÄ®¶óÀåÀÇ ±â¿ï±â º¤Å͸¦ ½á¼ integrand¸¦ ³ªÅ¸³½ °Í. ¿¹: \( dV = \nabla V(\mathbf{x}) \cdot d\mathbf{s} = -\mathbf{E}({\mathbf x}) \cdot d\mathbf{s} \)
Áï, ¿ÏÀü¹ÌºÐÇü½ÄÀ» ÀáÀçÇÔ¼ö·Î ³ªÅ¸³½ °ÍÀ» ÀáÀçÇÔ¼öÀÇ Àü¹ÌºÐÀ̶ó ÇÑ´Ù.
- \( dV \)¿Í \( \nabla V \) ¸¦ ±¸º°ÇØ¾ß ÇÑ´Ù.
An example: \((a + b)^2 = a^2 + 2ab + b^2\).
We get the above from below.
\begin{align} (a + b)^2 & = (a + b)(a + b) \\ & = a^2 + ab + ab + b^2 \\ & = a^2 + 2ab + b^2 \end{align}
We find the value of an interesting integral: \begin{equation} \int_0^\infty \frac{x^3}{e^x-1}\,dx = \frac{\pi^4}{15}. \label{eq:sample} \end{equation} To find the above equation \eqref{eq:sample}, we solve.... This is from http://www.mathjax.orgMore LaTeX Use: http://docs.mathjax.org/en/latest/tex.html